Question

charged particle of charge q and mass M is released from rest in a uniform electric field neglecting the effect of gravity the kinetic energy of a charged particle after time T seconds is​

Answer 1

Answer:

(q^2 E^2 T^2)/2m

Explanation:

So, let field be E

So, Force on particle = qE

Therefore,acceleration of particle = qE/m

After time T, velocity v = qET/m

Therefore KE = (mv^2)/2 = (m q^2 E^2 T^2)/(2 m^2)

= (q^2 E^2 T^2)/2m