Question

Charges 2uC and luC are placed at corners A and B of square of side 5cm as shown in figure. The
amount of work to be done against the electric field in moving a charge of 1.0x10°C from C to Dis
a) 0.045)
b) 0.053 J
C с
[ ]
D. 5 cm
c) 0.017)
d) 0.034J
A А
91
B
42​

Answer 1

Answer:

Explanation:

Given data,

Charges(q)=2×10  

−6

C,

Distance(d)=3cm=3×10  

−2

m  

electric field(E)=2×10  

5

N/C.

Torque(τ)=?

We know that  

Torque(τ) to be measured

Torque=charge×distance×Electric field

Torque(τ)=(2×10  

−6

)×(3×10  

−2

)×(2×10  

5

)

=12×10  

−3

Nm