Question

Charges 5nC, -3nC, 2nC and 6nC are placed at the corners A,B,C and D of a square of side

√2m. Find the magnitude of force acting on a charge 4nC placed at the centre of the

square. ​

Answer 1

Answer:

is the centre of the square.

Where,

(Sides) AB=BC=CD=AD=10cm

(Diagonals) AC=BD=10

2

cm

AO=OC=DO=OB=5

2

cm

A charge of amount 1μC is placed at point O.

Force of repulsion between charges placed at corner A and centre O is equal in magnitude but opposite in direction relative to the force of repulsion between the charges placed at corner C and centre O. Hence, they will cancel each other. Similarly, force of attraction between charges placed at corner B and centre O is equal in magnitude but opposite in direction relative to the force of attraction between the charges placed at corner D and centre O. Hence, they will also cancel each other. Therefore, net force caused by the four charges placed at the corner of the square on 1μC charge at centre O is zero.