Question

Charges of +(10/3) * 10-9 are placed at each of the four comers of a square of side 8cm. The potential at the intersection of the diagonals is (A) 150 V2 Volt (B) 1500 2 Volt (C) 900 V2 Volt (D) 900 Volt​

Answer 1

Answer:

Charges of =+

3

10

×10

−9

C

side a=8cm

Potential at the centre 0

V=

4πϵ

0

(a/2)

1/2

4Q

where,

Q=

3

10

×10

−9

C

and a=8cm=8×10

−2

m

So,

V=4×9×109×103×10

−9

×8×10

−2

=1500×2

1/2

V

=1500

2

V

Explanation:

hope it helps