Question

Charges of 16 nanocoulomb, -16 nanocoulomb and 32 nanocoulomb are placed at the three corners A, C and D of a square of side 4 cm. Find the intensity of the field at the fourth corner B.​

Answer 1

Answer:

Charge of the particle =Q

mass =m

side =l

maximum speed attained by any one of the particle.

So, Total PE=

r

3KQ

2

2

1

QV

2

=

4πϵ

0

ml

1

or, V=Q

2πϵ

0

mL

1