Question

Charges of 16 nanocoulomb, -16 nanocoulomb and 32 nanocoulomb are placed at the three corners A, C and D of a square of side 4 cm. Find the intensity of the field at the fourth corner B.​

Answer 1

Answer:

Electric intensity , E=14πε0qd2

Here EA=EC=9×109×10×10−9/9

=10NC−1

EB=9×109×20×109(32–√)2

=10N/C−1

Resultant of EA&EC is (2–√×EA)=102–√

EB is along 2–√×EA

Resultant electric intensity at D is equal to

(2–√×EA)+EB=10+102–√

24.14NC−1