Question

Charith is 15 years old than Hardin. After six years their ages will be in ratio 3:2 find their ages

Answer 1

Answer:

• The age of Hardin's = 51 years

• And the age of Charith 's = 66 years

Given :

• Charith is 15 years old than Hardin.

• After six years their ages will be in ratio 3:2.

To find :

• Their ages =?

Step-by-step explanation:

Let, the age of Hardin's be x

Then, Charith's age be, x + 15.

After six years Hardin's age = x + 6.

After six years Charith's age = x + 15 + 6 => x + 21

According to the given question :

➺ x + 6 / x + 21 = 3/2

➺ 2(x + 6) = 3(x + 21)

➺ 2x + 12 = 3x + 63

➺ 2x - 3x = 63 - 12

➺ - x = 51 [ignore negative]

So, x = 51

Hence,

The age of Hardin's => x = 51 years

And the age of Charith 's => x + 21 => 21 + 15 = 66 years

Answer 2

Step-by-step explanation:

Given:

• Charith is 15 years older than Hardin
• After 6 six years their ages will be in ratio 3:2

To Find:

• Present ages of both

Solution: Let Hardin's age be x years then, Charith's age = x + 15

★ After 6 years their ages ★

• Hardin's age = x + 6 years
• Charith's age = x + 15 + 6 = x + 21 years

A/q

† After 6 years their ages will be in Ratio: 3:2

x + 6 = 2

x + 21 = 3

$\small\implies{\sf }$ 3x + 18 = 2x + 42 ( Cross Multiplication)

$\small\implies{\sf }$ 3x – 2x = 42 – 18

$\small\implies{\sf }$ x = 24

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So, Their ages =

• Hardin's age = x = 24 Years

and

• Charith's age = x + 15 = 24 + 15 = 39 years