Question

Charlotte and Amelia were arranging chairs at a community hall. Charlotte arranged 9 chairs at a time whereas Amelia arranged 12 chairs at a time. If they ended up arranging the same number of chairs, what is the minimum number of chairs that each one could have arranged?

Answer 1

There are 8 chair on each side of the table.

Let the sides be represented by A and B.

Let four persons sit on side A, then number of ways of arranging 4 persons on 8 chairs on side A=

8

P

4

And two persons sit on side B.

The number of ways of arranging 2 persons on 8 chairs on side B=

8

P

2

The remaining 10 persons can be arranged in remaining 10 chairs in 10! ways.

Hence, the total number of ways in which the persons can be arranged is

8

P

4

×

8

P

2

×10!=

4!6!

8!8!10!

PLS BRAINLIEST AND 1 THANKS FOR SMALL ACCOUNT PLS HELP

Answer 2

Answer:

36

Step-by-step explanation: