Question

Charlotte has given Ron a BIG bar of chocolate for Valentine’s day! He decides to break the bar into its individual squares to share with their family. The bar is six squares long and thirteen squares high. How many times will he have to break the bar?

Answer 1

Since the options are not given, I am giving an assumed answer.

The correct answer should be - 77 times.

Since the chocolate bar is 6 squares long and 13 squares high, after being broken into individual squares, there should be 13 x 6 = 78 squares.

However, since each break will give 2 pieces (n + 1), a total of 77 breaks will give (n + 1) = 78 squares of chocolate squares.

Answer 2

Solution :-

Ron has 13 × 6 chocolate bar and he decides to split it into individual 1 by 1 squares for his family. 

So, we need to find the area of the bar for it.

Length of the chocolate bar = 13 units

Breadth of the chocolate bar = 6 units

Area of rectangular bar = L*B

⇒ 13*6

= 78 square units

So, there are 78 squares in the chocolate.

We need to consider that for the last two remaining squares, Ron will have to break the bar once because after breaking the bar into 76 squares, there will be two squares left. Ron will need to break it for 77th time only. He will have to break the chocolate bar into one square less than its area.

⇒ Area - 1

⇒ 78 - 1

⇒ 77 times

So, the answer is 77 times.