Question

charu and nirmal work complete in 15,10 days.they are working both after some days charu was gone,remaining work nirmal completed in 5 days.charu how many days worked.

Answer 1

Hey mate !!

Here's your answer !!

Let us first consider the amount of work done by both in a single day:

Charu = 15 days

Hence in 1 day he has completed 1/15 th of work.

Nirmal = 10 days

Hence in one day he has completed 1/10 th of work.

So if they both work together they complete the work in x days

So amount of work done in a single day = 1/x th of work

=> $\frac{1}{10} + \frac{1}{15} = \frac{1}{x}$

Taking LCM we get,

= [tex] \frac{15+10}{15*10} = \frac{1}{x} [/tex]

= $\frac{25}{150} = \frac{1}{x}$

= $\frac{1}{6} = \frac{1}{x}$

=> x = 6 days

So total number of days = 6 days

Hope it helps !!

Cheers !!

Answer 2

Given:

Charu completes in 15 days and Nirmal completes in 10 days

After Charu left, Nirmal completed it in 5 days

To find:

Calculate the number of days to complete the work

Solution:

Let us consider the total amount of “work done” by both in a single day:

Charu = 15 days

So in 1 day, he completed $\frac {1}{15}th$ of the work.

Nirmal = 10 days

So in 1 day, he completed $\frac {1}{10}th$ of the work.

If both work together, then they complete the work in x days

Then the “total amount of work” done in a single day $= \frac {1}{x} th$ of the work

Taking LCM we get,

$\frac {1}{10} + \frac {1}{15} = \frac {1}{x}$

$\frac {10+15} { 15 \times 10} = \frac {1}{x}$

$\frac {25} {150} = \frac {1}{x}$

$\frac {1}{6} = \frac {1}{x}$

Therefore x = 6 days