Cheack ulhethes 6 can end with the degit 0 for any natiural number
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In order to check whether 6n can end with the digit 0 for any natural number n, let us find the factors of 6.
It’s seen that the factors of 6 are 2 and 3.
\begin{aligned} &\text { So, } 6^{n}=(2 \times 3)^{n}\\ &6^{n}=2^{n} \times 3^{n} \end{aligned}
So, 6
n
=(2×3)
n
6
n
=2
n
×3
n
Since, the prime factorization of 6 does not contain 5 and 2 as its factor, together. We can thus conclude that 6n can never end with the digit 0 for any natural number n.
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