Question

cheak whether the (x-3)(2x+1)=x(x+5) is a quadratic equation​

Answer 1

Answer:

L.H.S = R.H.S

(x-3)(2x+1) = x(x+5)

we can clearly see from here itself that this equation is a quadratic equation as on opening the brackets :

2x^2 -6x +x-3 = x^2 +5x

on solving it further...

x^2 -10x -3 =0

so clearly, this is a quadratic equation...

as the highest power(degree) of the equation is 2

hope it helps... :)

Answer 2

Answer:

(x-3)(2x+1)=x(x+5)

x-3)(2x+1)=x(x+5)2x²+x-6x-3= x²+5x

x-3)(2x+1)=x(x+5)2x²+x-6x-3= x²+5x2x²-5x-3= x²+5x

x-3)(2x+1)=x(x+5)2x²+x-6x-3= x²+5x2x²-5x-3= x²+5x2x²-x²-5x-5x-3=0

x-3)(2x+1)=x(x+5)2x²+x-6x-3= x²+5x2x²-5x-3= x²+5x2x²-x²-5x-5x-3=0x²-10x-3=0

x-3)(2x+1)=x(x+5)2x²+x-6x-3= x²+5x2x²-5x-3= x²+5x2x²-x²-5x-5x-3=0x²-10x-3=0Yes, Its a quadratic equation because it's in the of ax²+bx+c=0