Question

check 0 is a term of this ap :31,28,25

Answer 1

Here a= 31 ,d=28-31=-3
let an be 0 
an=a+(n-1)d
0=31+(3-1)-3
0=31-6
0=25
so 0 is the term 25

Answer 2

Answer:

Step-by-step explanation:

a=31

d=28-31=-3

tn=a+(n-1)d

0=31+(n-1)(-3)

-31=-3(n-1)

31/3=n-1

n=(31+3)/3

n=34/3

as n is fractional therefore 0 is not a term of the AP