check (2,1) is the solution of 3x+5y =13
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Answer:
no these are not x and y of this equation
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Answer:
Step-by-step explanation:
Let (2,1) is the solution of 3x+5y =13
Now put x=2, y=1
equation became - LHS = 3*2 + 5*1 = 6 + 5 = 11 ≠ 13
LHS ≠ RHS
∴(2,1) is NOT the solution of 3x+5y =13
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