check 3 and -2 are the zeros of the polynomial x2 - x- 6 or not. friends tell me fast
Answers
To check :
Whether 3 and (-2) are zeros of x² - x - 6 = 0
SOLUTION :
Given , p(x) = x² - x - 6
If 3 and -2 are zeros of given polynominal then
p(3) and p(-2) must be zero
Therefore we will find p(3) and p(-2)
- p(3)
p(3) = (3)² - (3) + 6
p(3) = 9 - 3 - 6
p(3) = 9 - 9
p(3) = 0
As p(3) = 0 ,
3 is zero of x² - x - 6
- p(-2)
p(-2) = (-2)² - (-2) - 6
p(-2) = 4 + 2 - 6
p(-2) = 6 - 6
p(-2) = 0
As p(-2) = 0,
(-2) os zero of x² - x - 6
Therefore , both 3 and -2 are zeros of polynomial x² - x - 6
Answer:
Step-by-step explanation:
If 3 and -2 are zeros of given polynominal then
p(3) and p(-2) must be zero
Therefore we will find p(3) and p(-2)
p(3)
p(3) = (3)² - (3) + 6
p(3) = 9 - 3 - 6
p(3) = 9 - 9
p(3) = 0
As p(3) = 0 ,
3 is zero of x² - x - 6
p(-2)
p(-2) = (-2)² - (-2) - 6
p(-2) = 4 + 2 - 6
p(-2) = 6 - 6
p(-2) = 0
As p(-2) = 0,
(-2) os zero of x² - x - 6
Therefore , both 3 and -2 are zeros of polynomial x² - x - 6