Question

check -3and 3 are the zeros of the polynomial x2-9 named p(x)​

Answer 1

$\bold \blue{answer}$

sum of zeros = -b/a = -3 = -(-3)/1 = 3/1

product of zeros = c/a = 3 = 3/1

so, a = 1 , b = 3 and c = 3

➡️ax²+bx+c = 0

➡️1x²+3x+3=0

➡️x²+3x+3 = 0

Hope this helps you❤️