Check 4^2n can end with digit 0 for any natural no n
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This is not possible beacuse 4n =22n; so the only prime in the factorization of 4n is 2. So the uniqueness of the Fundamental Theorem of Arthmetic guarantees that there are no other primes in the factorization of 4n . So there is no natural number n for which 4n ends with the digit zero.
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