Question

Check accuracy of E=mgh+mv^2

Answer 1

Answer:

If you mean dimension wise,

As we know Energy=Joules/Second or M¹L²T`²

This will be RHS, now we if if it is dimensionally correct we would have to prove R.H.S=L.H.S

For L.H.S

mass=M

g= acceleration =L¹T`²

v= dist/time= L¹T`¹

Adding as per question

[M][LT`²][L] + (ignore 1/2 cause its constant) [M][LT`1]

==> [M²L³T`³]

since R.H.S ≠L.H.S

*its not accurate*

(`) is used instead of (-) Sorry.

Explanation: