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Answer 1

Answer:

42a² - 8a( a - 1 ) - 7a( 1 + 5a ) + a ( a - 1 ) is equal to 0

Explanation

First, let's distribute the numbers to get a read of parentheses/brackets

⟹ 42a² - 8a( a - 1 ) - 7a( 1 + 5a ) + a ( a - 1 )

⟹ 42a² -8a² + 8a - 7a( 1 + 5a ) + a ( a - 1 )

⟹ 42a² -8a² + 8a - 7a - 35a² + a ( a - 1 )

⟹ 42a² - 8a² + 8a - 7a - 35a² + a² - a

Now let's combine all the like terms, so that the expression can be simplified.

⟹ 42a² - 8a² + 8a - 7a - 35a² + a² - a

⟹ ( 42a² - 8a² - 35a² + a²) + 8a - 7a - a

⟹ [ ( 42 - 8 - 35 + 1)a² ] + 8a - 7a - a

⟹ [ ( 0 )a² ] + 8a - 7a - a

Here, coefficient of a² is 0, that means a² is being multiplied by 0, so the value of 0a² is 0. As zero is the additive identity, this won't affect the result.

⟹ 8a - 7a - a

⟹ ( 8 - 7 - 1 ) a

⟹ ( 8 - 8 ) a

⟹ 0a

⟹ 0

The value of the given expression is 0.

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