Question

Check by the method of dimension whether the following equation are correct that is E=mc²

Answer 1

$e = m {c}^{2}$

$l.h.s = (e) = (m {l}^{2} {t}^{ - 2})$

$r.h.s = (m {c}^{2} ) = (m)( {c}^{2})$

$(m)(( {t}^{ - 1}) ^{2} )$

$(m)( {l}^{2} {t}^{ - 2} )$

$(m {l}^{2} {t}^{ - 2} )$

$lhs = rhs$

$e = m {c}^{2}$

$\huge\mathcal{Proved♡}$