Math, asked by nithyashree5, 1 year ago

check check whether the roots of the quadratic equation 1 by X - 2 + 2 by x minus 1 is equal to 6 by X real or not if S find the roots X not equal to 0, 1, 2

Answers

Answered by prabhakarsharma2004
0

Answer:

Step-by-step explanation:

5x^2-6x-2=0

So check roots,

B^2-4ac=0

(-6 )^2-4×5×(-2)=0

36-40=0

-4>0

It has real roots.

By completing square method,

5x^2-6x-2=0

Divide by 5

X^2-6/5x-2/5=0

X^2-2×x×3/5+(3/5)^2=2/5+*3/5)^2

(X-3/5)^2=2/5+9/25

(X-3/5)^2=10+9/25

(X-3/5)^2=19/25

(X-3/5)=+_root19/5

X=+root19/5+3/5

****X=root19+3/5

****X=root19-3/5

I HOPE ARE YOU UNDERSTAND.

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