Question

Check correctness of the equation-
Time period of a pendulum T=2π✓l÷g

Answer 1

Answer:

Unit check ness.

See explaimatiin.

Explanation:

but, we check the nature of units on both sides of equation.

For L.H.S

L.H.S = T

unit of time is second

L.H.S= s

For R.H.S

2pi is constant so have no unit.

length has unit meter.

unit if gravitational constant is m/s^2

So

R.H.S = 2π✓l÷g

R.H.S = √m÷m/s^2

= √s^2

= s

since both sides are equal in unit.

So given equation is correct.