Question

Check even or odd in java without using if else, switch case and ternary operator.

Write in Java. It's very easy. ​

Answer 1

Without Using any Operator

int number = 13;

String[] trick = { "even", "odd" };

System.out.println(number + " is " + trick[number % 2]);

Answer 2

Using Bitwise AND operator

import java.util.Scanner;

public class EvenOdd {

   public static void main(String[ ] args) {  

       System.out.print("Enter a number - ");

       int number = new Scanner(System.in).nextInt( );

       boolean isEven = (number & 1) != 1;

       System.out.println("Is Even - " + isEven);

   }

}

Sample I/O:

   Case 1:

       Enter a number - 12

       Is Even - true

   Case 2:

       Enter a number - 11

       Is Even - false