Question

Check if (√2,4√2) is a solution of
equation x-2y = 4​

Answer 1

Answer:

$(x,y)=(\sqrt{2},4\sqrt{2})\\\therefore \ \ \ \ x=\sqrt{2}\\and \ \ y= 4\sqrt{2}\\\\\therefore x-2y=4\\\therefore (\sqrt{2}) - 2(4\sqrt{2}) =4\\\therefore \sqrt{2} - 8\sqrt{2}=4\\\therefore -7\sqrt{2} \neq 4\\\\Thus \ (\sqrt{2},4\sqrt{2}) \ is \ not \ a \ solution \ of \ [x-2y=4]$

Step-by-step explanation: