Check if 6^n can end with the digit 0 for any natural number n
Answers
Answered by
1
6^n will not have 0. Because 6 multiplied by 6 gives 6 as the last digit.
Let's solve for it. 6^1=6=2*3
6^2=6^1*6=36=2^2*3^2
6^3=6^2*6=216
Then let's take vice versa
6^n end with 0. It can only happen if one of the factors is 5.
6^n/6^(n-1)= 6 or 5+1. So proved
Let's solve for it. 6^1=6=2*3
6^2=6^1*6=36=2^2*3^2
6^3=6^2*6=216
Then let's take vice versa
6^n end with 0. It can only happen if one of the factors is 5.
6^n/6^(n-1)= 6 or 5+1. So proved
Similar questions