Chemistry, asked by blackpinf4ever, 1 year ago

Check if it's correct
OXIDATION NUMBER
DON'T ANSWER IF U DON'T KNOW!

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Answered by Anonymous
2

Answer \:  \\  \\ ca(ocl)cl \\  \\ let \:  \:  \: the \:  \:  \: oxidation \:  \: number \:  \:  \: of \:  \: cl \:  \: be \:  \: x \:  \:  \\  \\  + 2 - 2 + x + x = 0 \\  \\ 2x = 0 \\  \\ x =  \frac{0}{2}   \\  \\ x = 0 \\  \\ so \:  \: the \:  \: oxidation \: number \: of \:  \: cl \:  \:  \: is \: 0


blackpinf4ever: I asked if what I did was correct or wrong
Anonymous: yeah! your procedure is absolutely right.
blackpinf4ever: Ty!
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