Check if R: Z → Z, R = {(a, b) |2 divides
a-b} is equivalence relation.
Answers
SOLUTION
TO CHECK
Check if R: Z → Z, R = {(a, b) |2 divides a-b} is equivalence relation.
EVALUATION
Here the given relation is
R : Z → Z such that R = {(a, b) |2 divides a -b}
CHECKING FOR REFLEXIVE
Let a ∈ Z
Since 2 divides a - a
So (a, a) ∈ R
So R is Reflexive
CHECKING FOR SYMMETRIC
Let a, b ∈ Z and (a, b) ∈ R
⇒2 divides a - b
⇒2 divides - ( b - a )
⇒2 divides ( b - a )
⇒(b, a) ∈ R
Thus (a, b) ∈ R implies (b, a) ∈ R
So R is symmetric
CHECKING FOR TRANSITIVE
Let a, b, c ∈ Z
Also let (a, b) ∈ R and (b, c) ∈ R
⇒2 divides a - b and 2 divides b - c
⇒2 divides ( a - b + b - c )
⇒2 divides ( a - c )
⇒(a, c) ∈ R
Thus (a, b) ∈ R and (b, c) ∈ R implies (a, c) ∈ R
R is transitive
Hence R is an equivalence relation
━━━━━━━━━━━━━━━━
Learn more from Brainly :-
The basis {(1,0,0),(0,1,0),(0,0,1)} of the vector space R³(R) is known as
https://brainly.in/question/24574737
2. Prove that the inverse of the product of two elements of a group is the product of the inverses taken in the reverse ord...
https://brainly.in/question/22739109