Question

Check if (root 2, 4root2) is a solution of the equation x-2y=4

Answer 1

Given solution : - (√2 , 4√2)

Equation : - x - 2y = 4

Verification : -

x - 2y

= √2 - (2 × 4√2)

= √2 - 8√2

= - 7√2

- 7√2 ≠ 4

So, the given values are not a solution of the equation.

Answer 2

Given,

Equation: x - 2y = 4.

To find,

Check if (√2, 4√2) is a solution to the equation.

Solution,

When a solution to an equation is given, the solution must satisfy the equation.

So, a given solution can be verified by simply substituting the values into the equation, and checking if it holds true.

Here, the given equation is,

x - 2y = 4, and

the point is (√2, 4√2).

Substituting the point  (x = √2 and y = 4√2) in the equation on LHS,

LHS:

x - 2y

= √2 - 2(4√2)

= √2 - 8√2

= -7√2.

But,

RHS = 4.

Clearly,

-7√2 ≠ 4

⇒ LHS ≠ RHS.

Therefore,  (√2, 4√2) is not a solution of the given equation x - 2y = 4.