Question

Check if the given numbers are a perfect cube,
(a) 216
(b) 567
(c) 125
(d ) 343
(e) 250
(f) 1331
(g) 1729
(h) 3375​

Answer 1

Answer:

216;125;343;1331;3375 are a perfect cube

Step-by-step explanation:

hope it helps you!!!!

Answer 2

Answer:

 Here is your answer

a) $\sqrt[3]{216} =$  you can do it by factorisation method

   216 = you will get 2*2*2*3*3*3

   so you have to check that 2*3  = 6

  so here you can get 6 three times .

 $\sqrt[3]{216}$ = 6

so here 216 is the cube root of 6

b) $\sqrt[3]{567}$ = by looking at the by factorisation method you cant get perfect        

    square

    so there is no  perfect cube root of 567

c)$\sqrt[3]{125}$ = we have got the numbers by factorisation method

    125 = 5*5*5

  $\sqrt[3]{125}$ = 5

 so here 5 is the perfect cube of  125

d) $\sqrt[3]{343}$= we have got the numbers by factorisation method

   343 = 7*7*7

   $\sqrt[3]{343}$ =  7

 so here 7 is the perfect cube  of 343

e) $\sqrt[3]{250}$ = by looking at the by factorisation method you cant get perfect        

    square

so there is no perfect cube  root of 250

f)$\sqrt[3]{1331}$=we have got the numbers by factorisation method

  1331 = 11*11*11

  so here 11 is the perfect cube root of 1331

g)$\sqrt[3]{1729}$ = by looking at the by factorisation method you cant get perfect        

    square

     so there is no perfect cube  root of 1729

h)$\sqrt[3]{3375}$ = we have got the numbers by factorisation method

  3375 =  15*15*15

  so here  15 is the perfect cube root of 3375

 Hope it helps you