check if the sum of all possible 3digit numbers that can be formed using the digits of 547 is divisible by the sum of its own digits find the other factors of the sum
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Sum of digits = 1 + 2 = 3 3 is divisible by 1 but ... Approach: First find the sum of the digits of the number then one by one check, whether the calculated sum is divisible by all the digits of the number. If for some digit it is not divisible then print No else print Yes.
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