check if X + 1 is a factor of 5 x cube + 4 x square minus 3 x minus 6
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Answered by
1
bhai first find zero of x+1 then put the value of x if ans is 0 then yes otherwise no
meerasadhvini:
not ok
Answered by
3
put x= -1
![5( { - 1)}^{3} + 4( { - 1)}^{2} - 3( - 1) - 6 \\ = - 5 + 4 + 3 - 6 \\ = - 11 + 7 \\ = - 4 \\( x + 1) \: is \: not \: a \: factor 5( { - 1)}^{3} + 4( { - 1)}^{2} - 3( - 1) - 6 \\ = - 5 + 4 + 3 - 6 \\ = - 11 + 7 \\ = - 4 \\( x + 1) \: is \: not \: a \: factor](https://tex.z-dn.net/?f=5%28+%7B+-+1%29%7D%5E%7B3%7D++%2B+4%28+%7B+-+1%29%7D%5E%7B2%7D++-+3%28+-+1%29+-+6+%5C%5C++%3D++-+5+%2B+4+%2B+3+-+6+%5C%5C++%3D++-+11+%2B+7+%5C%5C++%3D++-+4+%5C%5C%28+x+%2B+1%29+%5C%3A+is+%5C%3A+not+%5C%3A+a+%5C%3A+factor)
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