Question

Check in which case the first polynomial is a factor of the second polynomial by dividing the second polynomial by the first polynomial : (i) t2 - 3 2t4 + 3t3 - 2t2 - 9t - 12​

Answer 1

Step-by-step explanation:

g(x) = t² - 3 = 0

g(x) = t = √3

p(x) = 2t⁴ + 3t³ - 2t² - 9t - 12 = 9

p(√3) = 2√3⁴ + 3√3³ - 2√3² - 9√3 - 12 = 0

p(√3) = 2*3² + 3*3√3 - 2*3 - 9√3 - 12 = 0

p(√3) = 18 + 9√3 - 6 - 9√3 - 12 = 0

p(√3) = 18 - 18 = 0

p(√3) = 0 = 0

Hence prooved.

I hope it will help you.

Pls mark me as brainliest if you are satisfied with the answer.