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in ∆ADB and ∆ADC
AD=AD. (common)
angleADB=angleADC. (each 90°)
BD=CD. (sinceAD is the perpendicular
bisector of BC)
∆ADB=~∆ADC. by SAS congruent rule
AB=AC. by cpct
therefore,∆ABC is an isosceles triangle...
................mark it as brainliest later
AD=AD. (common)
angleADB=angleADC. (each 90°)
BD=CD. (sinceAD is the perpendicular
bisector of BC)
∆ADB=~∆ADC. by SAS congruent rule
AB=AC. by cpct
therefore,∆ABC is an isosceles triangle...
................mark it as brainliest later
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