Question

Check out the 78 th question with explaination...plz...

Answer 1

let the angle be

x=60

we assume there is uniform resistance distribution and

lenght of whole wire=l

therefore lenght of wire with x=60 is=60/360*l

=l/6

if resistance of whole wire is 6 ohm then resistance of l/6 part is 6/6=1 ohm

resistance of the leftover part of wire=5 ohm

as these 2 arts are connected in parallel ( 1 ohm and 5 ohm) the final resistance is given by

1/Reff=1/5+1/1

1/Reff=6/5

Reff=5/6 ohm

therefore the final resistance is 5/6 ohm