Question

check q(x)= 2x-3 is a factor of g(x) 6x^3 -19x^2 +29x -21​

Answer 1

Answer

No q(x) is a factor of g(x)

Step-by-step explanation:

q(x) = 2x-3

0 = 2x-3

3 = 2x

3/2 = x

g(x) = 6x^3 - 19x^2 - +29x - 21

g(x) = 6(3/2)^3 - 19(3/2) + 29(3/2) - 21

g(3/2) = 6(27/8) - 19(9/4) + 87/2 - 21

g(3/2) = (3×27/4) - (171/4) + 87/2 - 21

g(3/2) = 81/4 - 171/4 + 87/2 - 21

Taking their L.C.M

L.C.M of 4 , 2 , 1 = 4

g(3/2) = 81 - 171 + 174 -84/4

g(3/2) = 0/4

g(3/2) = 0

Since the result is Zero , q(x) is a factor of g(x) .

Hope it helps .