Check that (x - 2/3) is a multiple of
p(x) = 9x² – 3x²+x-5
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Answered by
1
9(2/3)_3(2/3)^2 + 2/3 _ 5 { x _ 2/3 = 0
x = 2/3 }
= _ 1/3
the answer is not zero hence (x _ 2/3) is not a multiple of p(×)
x = 2/3 }
= _ 1/3
the answer is not zero hence (x _ 2/3) is not a multiple of p(×)
lsmuskan:
wlcmmm
Answered by
1
p(-1) = 6(-1)^2 + -1-5
= 0
there fore x= -1
= 0
there fore x= -1
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