Math, asked by RagingEmber, 1 year ago

check the answer of this question.if a^x=b and b^y=c and c^z=a.prove that xyz=1

ans:a^x+b^y+c^z=a^1+b^1+c^1
a^x=a^1
x=1

b^y=b^1
y=1

c^z=c^1
z=1

xyz=1
1*1*1=1

Answers

Answered by graxx
9
Hi there

Your answer is :-


a^xyz

=(a^x)^yz

=b^yz

=(b^y)^z

=c^z

=a

by comparision xyz=1 proved



Hence Your answer is Correct


Thank You
Answered by Anonymous
0
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