Math, asked by niraj8848, 1 month ago

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Answered by vinayaknautiyal41
1

Answer:

We know, `2sin^2x = 1-cos2x`

`:. L.H.S. = 2(asin^2(C/2)+csin^2(A/2))`

`=a(1-cosC)+c(1-cosA)`

`=a+c -(acosC+c cosA)`

From projection formula,

`b = (acosC+c cosA)`

`:. a+c -(acosC+c cosA) = a+c - b = R.H.S.`

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