Check the consistency of the formula1/2mv2+ma=F
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Given that,
The equation is
1/2 mv^2 = mgh
Taking left hand side
Kinetic energy K.E. = 1/2 mv^2
Here, 1/2 is constant
m = mass
v = velocity
Dimension formula of kinetic energy
1/2 mv^2
1/2 mv^2 =[M][L^2T^-2]
Taking right hand side
Dimension formula of potential energy
Potential energy P.E = mgh
Here, g = acceleration due to gravity
h = height
m = mass
mgh = [M][LT^-2][L]
mgh = [M][L^2T^-2]
The Left hand side equal to right hand side.
Hence, The equation is correct.
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