Check the continuity of f (x)={ (x2-x-6)/(x2 -2x-3),x not equal to 3;5/3,x not equal to 3 at x=3
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x²-x-6=x²-3x+2x-6=x(x-3)+2(x-3)=(x+2)(x-3)
x²-2x-3=x²-3x+1x-3=x(x-3)+1(x-3)=(x+1)(x-3)
x²-x-6/x²-2x-3=(x+2)(x-3)/(x+1)(x-3)=x+2/x+1
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