Question

Check the correctness of dimension of escape velocity

Answer 1

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The dimensional correctness of the relation escape velocity, v=√2GM/R is LT^-1 = LT^-1.

Given,

where,

v = escape velocity = ms^-1.

G = gravitational constant = Nm^2 / Kg^2.

M = mass = Kg.

R = radius = m.

we have,

v = ms^-1 = [LT^-1]