check
the correctness of equation
I 1/2 mv2-1/2mu2= F*X
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Answer:
This equation is correct
Explanation:
Given that,
F.S=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2F.S=
2
1
mv
2
−
2
1
mu
2
L.H.S represent the work and R.H.S represents the change in kinetic energy.
F = force
S = distance
We know that,
M represents of mass, L represents of distance and T represents of time.
Using dimension formula
[MLT^{-2}][L]=[M][LT^{-1}]^2-[M][LT^{-1}]^2[MLT
−2
][L]=[M][LT
−1
]
2
−[M][LT
−1
]
2
[ML^2T^{-2}]=[ML^2T^{-2}]-[ML^2T^{-2}][ML
2
T
−2
]=[ML
2
T
−2
]−[ML
2
T
−2
]
L.H.S=R.H.S
SO, We can say that this equation is correct.
Hence, This equation is correct
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