Question

Check the correctness of equation T=2π by dimesional analysis

Answer 1

Answer:

We prove this equation dimensionally.

We prove this equation dimensionally.Time = (T)

We prove this equation dimensionally.Time = (T)Length = (l)

We prove this equation dimensionally.Time = (T)Length = (l)g means acceleration due to gravity = (lt^-2)

We prove this equation dimensionally.Time = (T)Length = (l)g means acceleration due to gravity = (lt^-2)Pi and 2 has no dimension because they are constant.

We prove this equation dimensionally.Time = (T)Length = (l)g means acceleration due to gravity = (lt^-2)Pi and 2 has no dimension because they are constant.Now we square both sides we get

We prove this equation dimensionally.Time = (T)Length = (l)g means acceleration due to gravity = (lt^-2)Pi and 2 has no dimension because they are constant.Now we square both sides we getT^2 = 4pi^2 (l/g)

We prove this equation dimensionally.Time = (T)Length = (l)g means acceleration due to gravity = (lt^-2)Pi and 2 has no dimension because they are constant.Now we square both sides we getT^2 = 4pi^2 (l/g)T^2 = L/LT^-2

We prove this equation dimensionally.Time = (T)Length = (l)g means acceleration due to gravity = (lt^-2)Pi and 2 has no dimension because they are constant.Now we square both sides we getT^2 = 4pi^2 (l/g)T^2 = L/LT^-2T^2 = L × T^2 / L

We prove this equation dimensionally.Time = (T)Length = (l)g means acceleration due to gravity = (lt^-2)Pi and 2 has no dimension because they are constant.Now we square both sides we getT^2 = 4pi^2 (l/g)T^2 = L/LT^-2T^2 = L × T^2 / LT^2 = T^2

We prove this equation dimensionally.Time = (T)Length = (l)g means acceleration due to gravity = (lt^-2)Pi and 2 has no dimension because they are constant.Now we square both sides we getT^2 = 4pi^2 (l/g)T^2 = L/LT^-2T^2 = L × T^2 / LT^2 = T^2HENCE PROVED.

Explanation:

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