Question

Check the correctness of following equation by dimensional analysis F d =1/2 mu²-1/2 mv²

Answer 1

Hi

Answer:

dimensionally incorrect

Explanation:

so ,

we know that ,

m = mass = Kg

u = initial velocity = m/s

&

v= final velocity = m/s

so

[ M^1 L^2 T^2] - [M^1 L^2 T^2]

SO WE GET ,

[M^0 L^0 T^0 ]

which is dimensionally no value

hence it is dimensionally incorrect

gud day