Check the correctness of formula v² = u² + 2as by using dimensional analysis.
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Dimensional formula for 'v' is LT^-1
So, 'v^2' will be L^2T^-2
Dimensional formula for 'u' is LT^-1
So, 'u^2' will be L^2T^-2
Dimensional formula for 's' is L
Dimensional formula for 'a' is LT^-2
2 is dimensionless
So, 'as' will be (L)(LT^-2) = L^2T^-2
By the principle of homogenity of dimensions, quantities can be added if and only if all of their dimensions are equal.
v^2 = u^2 + 2as
⇒ L^2T^-2 = L^2T^-2 + L^2T^-2
The formula v^2 = u^2 + 2as follows the priciple of homogenity of dimensions. So, the equation is dimensionaly correct.
So, 'v^2' will be L^2T^-2
Dimensional formula for 'u' is LT^-1
So, 'u^2' will be L^2T^-2
Dimensional formula for 's' is L
Dimensional formula for 'a' is LT^-2
2 is dimensionless
So, 'as' will be (L)(LT^-2) = L^2T^-2
By the principle of homogenity of dimensions, quantities can be added if and only if all of their dimensions are equal.
v^2 = u^2 + 2as
⇒ L^2T^-2 = L^2T^-2 + L^2T^-2
The formula v^2 = u^2 + 2as follows the priciple of homogenity of dimensions. So, the equation is dimensionaly correct.
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