Question

Check the correctness of T = $\sqrt[2\pi]{\frac{l}{g}}$

Answer 1

HEY !!! HERE IS YOUR ANSWER ##

HOPE IT HELPS ^_^

Answer 2

this can checked by method of dimensions.

$T = 2 \pi sqrt{\frac{l}{g}}$
$\implies RHS = {(L)}^{\frac{1}{2}} {( L {T}^{-2})}^{\frac{-1}{2}}$
${(L)}^{\frac{1}{2}} {(L)}^{\frac{-1}{2}} (T)$
$\implies R.H.S. = L.H.S.$

thus the equation is dimensionally correct.

hope it helps you if yes then please mark my answer as brainliest ☺️☺️.