Physics, asked by sushma3163, 1 year ago

check the correctness of the equation v2=u2+2as

Answers

Answered by sdbalakrishnan
1

Answer:(m/s)sq=(m/s)sq+m/s^2*m/s

([LT^-1])^2=(LT^-1)^2+[LT^-2] [L]

[L^2T^-2]=[L^2 T^-2]+[L^2T^-2]

Explanation:

This comes under the part dimensions.with help of the units in SI system we can solve this as abv done

Answered by dodiyaM001
18

Answer:

by using dimension...

Explanation:

v²=u²+2as

l.h.s. =  >   {v}^{2}  =  ({ {l}^{1}  {t}^{ - 1}})^{2}

  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  >  {l}^{2}  {t}^{ - 2}

r.h.s. =  >  {u}^{2}

 =  >  ({ {l}^{1} {t}^{ - 1}  })^{2}

 =  >  {l}^{2}  {t}^{ - 2}

2as =  {l}^{1}  {t}^{ - 2} ( {l}^{1}

 =  {l}^{2}  {t}^{ - 2}

L.H.S =R.H.S

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