Physics, asked by thero3535, 1 year ago

Check the correctness of the following equations
1. v2=u2+2as

rahulkhatri137: yes its correct

rahulkhatri137: V2=u2+2as

rahulkhatri137: dimensions of velocity is L*1T*-1

rahulkhatri137: Also as=v

rahulkhatri137: in add only same dimensional things can be added

rahulkhatri137: so u*2 +as(v*2)=v*2

rahulkhatri137: v has dimension L*1T-1

rahulkhatri137: Dimension of both sides are equal

Answers

Answered by Shamangi

v ^ 2 = u ^ 2 +2 as kdkdkffkfkkfdododod

thero3535: what is this

thero3535: this is wrong

rahulkhatri137: this is right

rahulkhatri137: both sides have safe dimension

rahulkhatri137: same dimensions

Answered by shashank100081

we have to prove 3 equation of motion
from 2 equation we will get s=ut+1/2at2
from 1 equation v=u+at
s=u(v-u)/a+1/2a(v-u/a)2
s=uv-u2/a+1/2a(v2+u2-2vu/a2)
uv-u2/a+v2+u2-2uv/2a (l.c.m of 2a and a is 2a)
s=2uv-2u2+v2+u2-2uv/2a
2as=v2-u2
HENCE PROOFED

rahulkhatri137: correctness of any formula is given by dimensions

rahulkhatri137: prove dimensional formula of both sides equal and it is proved

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Check the correctness of the following equations 1. v2=u2+2as

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Check the correctness of the following equations
1. v2=u2+2as