Check the correctness of the following equations
1. v2=u2+2as
rahulkhatri137:
yes its correct
V2=u2+2as
dimensions of velocity is L*1T*-1
Also as=v
in add only same dimensional things can be added
so u*2 +as(v*2)=v*2
v has dimension L*1T-1
Dimension of both sides are equal
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Answered by
1
v ^ 2 = u ^ 2 +2 as kdkdkffkfkkfdododod
what is this
this is wrong
this is right
both sides have safe dimension
same dimensions
Answered by
0
we have to prove 3 equation of motion
from 2 equation we will get s=ut+1/2at2
from 1 equation v=u+at
s=u(v-u)/a+1/2a(v-u/a)2
s=uv-u2/a+1/2a(v2+u2-2vu/a2)
uv-u2/a+v2+u2-2uv/2a (l.c.m of 2a and a is 2a)
s=2uv-2u2+v2+u2-2uv/2a
2as=v2-u2
HENCE PROOFED
from 2 equation we will get s=ut+1/2at2
from 1 equation v=u+at
s=u(v-u)/a+1/2a(v-u/a)2
s=uv-u2/a+1/2a(v2+u2-2vu/a2)
uv-u2/a+v2+u2-2uv/2a (l.c.m of 2a and a is 2a)
s=2uv-2u2+v2+u2-2uv/2a
2as=v2-u2
HENCE PROOFED
correctness of any formula is given by dimensions
prove dimensional formula of both sides equal and it is proved
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