check the correctness of the formula v^2=u^2+2as using dimensional analysis.
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HEY BUDDY !!!
HERE'S THE ANSWER!!!
______________________
▶️ First I'll write the dimeyof the term used here
⏺️v ( velocity ) = [ L T^-1 ]
⏺️u ( initial velocity ) = [ L T^-1 ]
⏺️a ( Acceleration ) = [ L T^-2]
⏺️s ( displacement ) = [ L ]
♠️ ( v )^2 = ( u )^2 + 2.a.s
=> [ L T^-1 ]^2 = [ L T^-1 ]^2 + [ L T^-2] . [ L ]
=> [ L T^-1]^2 = [ L T^-1 ]^2 + [ L^2 T^-2 ]
=> [ L T^-1]^2 = [ L T^-1 ]^2 + [ L T^-1 ]^2
✔️ L.H.S. = R.H.S.
▶️ Hence given formula is correct
HOPE HELPED
JAI HIND..
:-)
HERE'S THE ANSWER!!!
______________________
▶️ First I'll write the dimeyof the term used here
⏺️v ( velocity ) = [ L T^-1 ]
⏺️u ( initial velocity ) = [ L T^-1 ]
⏺️a ( Acceleration ) = [ L T^-2]
⏺️s ( displacement ) = [ L ]
♠️ ( v )^2 = ( u )^2 + 2.a.s
=> [ L T^-1 ]^2 = [ L T^-1 ]^2 + [ L T^-2] . [ L ]
=> [ L T^-1]^2 = [ L T^-1 ]^2 + [ L^2 T^-2 ]
=> [ L T^-1]^2 = [ L T^-1 ]^2 + [ L T^-1 ]^2
✔️ L.H.S. = R.H.S.
▶️ Hence given formula is correct
HOPE HELPED
JAI HIND..
:-)
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