Question

Check the correctness of the relation t=2π√l/g where t is the time period l is length of simple pendulum g is acceleration due to gravity

Answer 1

Answer:

Comparing X: = -g.x/l with X: = -w^2. x, we identify that w^2 = g/l which implies: w =√g/l

The period T = 2π /w =  2π   =    2π√l/g

                                       √g/l

Hence T = 2π√l/g

Explanation:

where X: = acceleration due to gravity   w = angular velocity